
3 Dec
2007
3 Dec
'07
6:22 a.m.
Thomas Davie wrote:
apfelmus wrote
Well, this problem doesn't make much sense in Haskell. How do you specify the subtrees u and v in the first place?
One could alway store a node's depth at each node -- then you must search for u and v, creating a list of what nodes you found at each depth, and finally, simply compare the lists -- O(n) in the depth of u and v.
Huh? I mean, are u and v node labels of type a? Or are they subtrees? In any case, they aren't "pointers" into the tree. In the case of node labels, a breath first search will take O(number of nodes of depth <= min (depth u) (depth v)) steps which is O(size of the tree) in the worst case. Regards, apfelmus