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On Mon, 14 Feb 2005 11:07:48 +0100, Daniel Fischer > And could one define
\f g h x y -> f (g x) (h y) point-free? sure, ((flip . ((.) .)) .) . (.)
\f g h x y -> f (g x) (h y)
point-free? sure, ((flip . ((.) .)) .) . (.)
Thomas
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