Re: [Haskell-cafe] Closures and pointfree functions

On Mon, 2007-09-03 at 19:47 +0200, Lars Oppermann wrote:

Dear all,

In the Haskell Wiki at http://www.haskell.org/haskellwiki/Closure there is an example for a function returning a closure given as f x = (\y -> x + y)

Another way to achieve the same effect would be to write f' x = (+) x

which to me as a beginner looks somewhat like pointfree style.

Would f' be considered to return a closure

Going backwards: Yes. The pointfree "solution" in this case would simply be f' = (+) Note that f x = \y -> x + y is written that way for emphasis and is identical to f x y = x + y