Re: [Haskell-cafe] How i use GHC.Word.Word8 wit Int ?

2009/5/20 z_axis@163.com :

Hi, friends

rollDice :: Word8 -> IO Word8 rollDice n = do   bracket (openFile "/dev/random" ReadMode) (hClose)       (\hd -> do v <-  fmap B.unpack (B.hGet hd 1)                  let v1 =  Data.List.head v                  return $ (v1 `mod` n) + 1) ..... blueIdx <- rollDice $ length [1..33]

Couldn't match expected type `Word8' against inferred type `Int'   In the second argument of `($)', namely `length yesBlue

I know "length [1..33]" is Int not Word8, but Word8 is enough here. Sincerely!

You can use fromIntegral to convert Integral types to other numeric types: fromIntegral :: (Integral a, Num b) => a -> b Prelude Data.Word> (fromIntegral (3 :: Int)) :: Word8 3 Watch out for overflow. Cheers, Bernie.