16 Feb
2010
16 Feb
'10
5:25 p.m.
On Tue, Feb 16, 2010 at 09:00:08AM -0800, Yves Parès wrote:
I was wondering: is the Haskell default runtime (that which uses only one processor) scheduler able to interrupt a thread which is currently calling to a C function in order to enable another haskell thread to progress? I think it can't, because I have starvation problems when I have a thread which calls inside its loop to a C function which makes a little "sleep".
Did you try marking the call as safe? Cheers, -- Felipe.