-----BEGIN PGP SIGNED MESSAGE----- Hash: SHA1 Greetings, We can currently do something like
class (Num a, Eq a) => Foo a where bar :: a -> a -> Bool bar = (==)
This means that our `a' has to be an instance of Num and Eq. Apologies for a bit of an artificial example. Is there a way however to do something along the lines of:
class Eq a => Foo a where bar :: a -> a -> Bool bar = (==)
class Num a => Foo a where bar :: a -> a -> Bool bar _ _ = False This would allow us to make an instance of Num be an instance of Foo or an instance of Eq to be an instance of Foo.
The compiler currently complains about multiple declarations. Is there currently a way to achieve this? The main issue I can see with this is that given an instance of both, Num and Eq, it wouldn't be possible to pick the correct default implementation. Purely a theoretical question. - -- Mateusz K. -----BEGIN PGP SIGNATURE----- Version: GnuPG v2.0.19 (GNU/Linux) iQIcBAEBAgAGBQJRjP0hAAoJEM1mucMq2pqX30wP/0d0TQHs4S3G5TBw+T1baI6n g/5k/YlPmSgS3FaO8JMQsb2uqL8dGPZGUN7d2ohwcigtXS88KWH4u4rTjrs1+p8o ktS+vIE4kEEedTAX6wmP2Zn+rvK2zFGboCafaX/a/IxT5CbwYZ97RrWCjzz1jlPs S/VlhNHcTQ7Cf/0pa0xJ1kbao+vBHiWtWjxcdzCT/6zS86+jm9vz8qrYT3TWUd3y AJXPBjRuXeyz+RDv18yrth7hMlAvaeoWzmC4gbGFHC68/Oq2l8kz+4dt6ApN+mIy l73wNjrU185YoZ2dkuKTIph8/BadgkD+9ktkgZZ/NlqxElc596BdbOcMfVk4rz4A 0nWqaLa4QctIthghJ1UNfKS8lQzkVVRT6e03LYdgPkqJm1HQxkjHL/WieV2NEoRf 1K9S4SVW8Aq/ML/Gmx782Z3jMECfnYWntf9gSOwFASB64tVej1iUxb7UsfxJAL1t ysf9MjcbZsHe3M/JAq4f8HtHoZoiIG/TTjD0yo74owssJDfOTDqmYMriyelcnUf6 hDCPZyUqLPMTNVx07T+gwfXJoE1HK20hzVe2o1dPBZ8Kb2KJbNg0+sUSB3/v6O8e EJ6w7aQ3OnZUACd1i2uLZiphMF8d8va4T8eTFUyROODHvaPv6netzr8gPcIXhpVO 5OwyMfO54cinZYen7+HR =iAYY -----END PGP SIGNATURE-----