Hi, you could do something like
instance (Show a,Read a) => Binary a where put = put . show get = fmap read get
But then you will need the following language extensions: FlexibleInstances, OverlappingInstances, UndecidableInstances I don't know how safe this is but it seems to work. Regards, Martin. Svein Ove Aas schrieb:
I'm in the process of writing a distributed filesystem (in haskell, yay), which of course means I'm using Binary for de/serialization.
Now, that's fine enough, but for simplicity (and for wireshark), I'd like to be able to have Binary fall back on an instance based on Show/Read for any type that lacks any other Binary instance..
Well, I understand why this would be somewhere between extremely hard and impossible in haskell '98, but I'm not entirely up on all the extensions, so I thought I'd ask - given every extension implemented in ghc 6.10.1, is there any reasonable way to do this? _______________________________________________ Haskell-Cafe mailing list Haskell-Cafe@haskell.org http://www.haskell.org/mailman/listinfo/haskell-cafe