Re: [Haskell-cafe] lazy patterns versus where-clauses

Peter Padawitz writes:

Is f(~p(x))=e(x) semantically equivalent to: f(z)=e(x) where p(x)=z?

Yep. See also http://en.wikibooks.org/wiki/Haskell/Laziness#Lazy_pattern_matching regarding lazy patterns. -- -David House, dmhouse@gmail.com