
Hi Paolino,
There are some functions similar to that in HList (Data.HList.HArray).
Check the repo http://code.haskell.org/HList for a version that uses
more type families / gadts.
Maybe there is a way to take advantage of the fact that you've
labelled the elements of the list, but extract isn't too bad if you
don't: http://lpaste.net/94210.
Regards,
Adam
On Sat, Oct 12, 2013 at 4:41 AM, Paolino
Hello everyone,
I'm still trying to resolve my problem. I try to restate it in a simpler way. Is it possible to write extract and update functions for L ?
import Data.Nat
data family X (n::Nat) :: *
data L (n::Nat) where Q :: L (Succ n) -> X n -> L n E :: L n
extract :: L Zero -> X n extract = undefined
update :: L Zero -> (X n -> X n) -> L Zero update = undefined
Thanks for hints and help
paolino
2013/10/7 Paolino
Hello, I'm trying to use a type class to select an element from a list. I would like to have a String "CC" as a value for l10'.
{-# LANGUAGE MultiParamTypeClasses, GADTs,FlexibleInstances, DataKinds ,TypeFamilies, KindSignatures, FlexibleContexts, OverlappingInstances, StandaloneDeriving, UndecidableInstances #-}
import Data.Nat import Data.Monoid
data family X (n::Nat) :: *
data L (n::Nat) where Q :: (Monoid (X n), Show (X n)) => L (Succ n) -> X n -> L n E :: Monoid (X n) => L n
deriving instance Show (L n) data instance X n = String String
instance Monoid (X n) where String x `mappend` String y = String $ x `mappend` y mempty = String "" deriving instance Show (X n)
class Compose n n' where compose :: L n -> L n -> X n'
instance Compose n n where compose (Q _ x) (Q _ y) = x `mappend` y compose _ _ = mempty
instance Compose n n' where compose (Q x _) (Q y _) = compose x y compose _ _ = mempty
l0 :: L Zero l0 = Q (Q E $ String "C") $ String "A"
l0' :: L Zero l0' = Q (Q E $ String "C") $ String "B"
l10' :: X (Succ Zero) l10' = compose l0 l0'
l00' :: X Zero l00' = compose l0 l0' {-
*Main> l00' String "AB" *Main> l10' String ""
-}
Thanks for help.
paolino
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