At the semantic level of "does my program compute correct results" they're identical. At the operational level of "how fast does my program run" they're different.
On August 23, 2016 5:09:19 PM GMT+10:00, Tom Ellis
On Mon, Aug 22, 2016 at 10:23:07PM -0700, wren romano wrote:
(.) f g = \x -> f (g x)
vs:
(.) f g x = f (g x)
has ramifications, though it's fairly easy to guess which one of
those
two will be most performant.
Are these not synonyms? What is the meaning of
fargs var = expr
if not
fargs = \var -> expr
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