Re: [Haskell-cafe] Dual Parser Failure???

PR Stanley wrote:

failure :: (Parser a) failure = \inp -> [] The code might contain some syntax errors and I'd be grateful for any corrections.

It looks right conceptually. Depending on the definition of Parser, you may need failure = P (\inp -> []) or whatever constructor name instead of P. The type checker will know. I don't know about dual parser failure.