Re: [Haskell-cafe] The C Equiv of != in Haskell

On Tue, May 29, 2007 at 11:20:27AM +0100, David House wrote:

On 29/05/07, Daniel McAllansmith wrote:

...

Just in case there was some sort of miscommunication, the actual answer to your question is (/=) :: a -> a -> Bool, as Neil said.

Almost, (/=) :: Eq a => a -> a.

Almost again! (/=) :: Eq a => a -> a -> Bool Best regards Tomek