[Haskell-cafe] Is id strict?

Hi all. I've seen two definitions of a 'strict function', which I'm trying to unite in my mind: 1) f is strict iff f _|_ = _|_. 2) f is strict iff it forces evaluation of its arguments. There is a large sticking point that in my minds seems to fit (1) but not (2): id. Clearly, id undefined is undefined, but I also don't think id forces evaluation of its argument. There was a mini-discussion concerning this topic last night on #haskell, but if there was a consensus conclusion, it passed me by. Thanks in advance. -- -David House, dmhouse@gmail.com