[Haskell-cafe] (a -> [b]) -> [a -> b] ?

Hi, while pondering over the four fours problem, I wondered: Is there a function of type (a -> [b]) -> [a -> b] It looks a bit like sequence when applied in the ((->) a) Monad: sequence :: [a -> b] -> a -> [b] but I was looking for the other direction. I came up with: \g -> map (\n a -> g a !! n) [1..] which has the desired type and functionality, but it looks rather inelegant and messy. Any better ideas? Thanks, Joachim -- Joachim "nomeata" Breitner mail: mail@joachim-breitner.de | ICQ# 74513189 | GPG-Key: 4743206C JID: joachimbreitner@amessage.de | http://www.joachim-breitner.de/ Debian Developer: nomeata@debian.org