[Haskell-cafe] Word8 literals in ByteString haddock?

Hey, according to http://hackage.haskell.org/packages/archive/bytestring/0.10.2.0/doc/html/Dat... I can write: split '\n' "a\nb\nd\ne" Can I really do that? I don't know of a way to make a '\n' literal be a Word8, so maybe these Haddocks are wrong? I guess they would apply for Data.ByteString.Char8, but this is Data.ByteString. Or is there a way? Niklas