Imagine if bar was a toplevel function
bar = case foo of
True -> " Foo";
False -> "Bar";
Keep in mind that indentation level starts at the function name, not at the
let keyword.
On Thu, Oct 3, 2013 at 2:31 PM, Corentin Dupont
Hi the list, why do this function doesn't compile (parse error):
test :: Bool -> IO () test foo = do let bar = case foo of True -> "Foo"; False -> "Bar" return ()
while this one does (just adding one space in front of True and False):
test :: Bool -> IO () test foo = do let bar = case foo of True -> "Foo"; False -> "Bar" return ()
Thanks!! Corentin
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