
Or, to keep it a fold,
asum xs = foldr go (fromMaybe empty) xs Nothing where
go x r Nothing = r (Just x)
go x r (Just prev) = prev <|> r (Just x)
On Jun 10, 2016 11:09 AM, "Dan Burton"
On Fri, Jun 10, 2016 at 05:37:41PM +0300, Юрий Сыровецкий (Yuriy Syrovetskiy) wrote:
It is so because in base library
asum = foldr (<|>) empty
What if it was defined
asum [] = empty asum [x:xs] = x <|> asum xs
Those are the same (assuming you mean (x:xs) instead of [x:xs]).
Tom _______________________________________________ Haskell-Cafe mailing list Haskell-Cafe@haskell.org http://mail.haskell.org/cgi-bin/mailman/listinfo/haskell-cafe
-- -- Dan Burton _______________________________________________ Haskell-Cafe mailing list Haskell-Cafe@haskell.org http://mail.haskell.org/cgi-bin/mailman/listinfo/haskell-cafe