Re: [Haskell-cafe] f(g(x), h(y)) - Correct syntax

On Mon, 11 Feb 2008, news@lyra.net wrote:

Hallo!

I have this code: ---------------------------------------- q1 :: EName -> [ApprenticeInfo] q1 c = [apprenticeInfo n | n <- allApprentices, member ((sq4 c) (firstOf5(n))) == True]

sq4 :: ESurname -> [IDB] sq4 c = (sq3 (sq1 (c)))

firstOf5 :: (a,b,c,d,e) -> a firstOf5 (n,_,_,_,_) = n

member :: [IDB] -> IDB -> Bool member [] y = False member(x:xs) y = (x==y) || member xs y

cf. List.elem