Re[3]: [Haskell-cafe] Go parallel

Hello Bulat, Tuesday, November 6, 2007, 3:43:30 AM, you wrote:

yes, that's true. but we can force evaluation of array elements:

task (i,j) = do putArray arr (i,j) (i*j) return $! getArray arr (i,j)

correct way: task (i,j) = do putArray arr (i,j) $! (i*j) this forces evaluation before writing value to array. not required for unboxed arrays -- Best regards, Bulat mailto:Bulat.Ziganshin@gmail.com