[Haskell-cafe] free monad versus operational for blackjack game

I'm studying the code for a blackjack game: See marked answer. http://codereview.stackexchange.com/questions/46809/blackjack-in-haskell It uses the operational package, and mentions one could write equivalent code using a free monad. But my question is, for this use case is there any benefit for using a free monad?