Hi,
Try to understand this:
type Matrix = [[Double]]
multSM :: Double -> Matrix -> Matrix
multSM d m = map (\ i -> map (\ j -> d*j ) i) m
Now try this for multSM (instead of the above definition)
multSM = map . map . (*)
Hope it helps,
On 2 February 2010 09:35, 조광래
hi I have a question about haskell coding.
Matrices
One of many ways to define matrices in Haskell is the list of matrix rows, where a row is a list of double precision oating point numbers:
type Matrix=[[Double]]
Using this type you should define the following functions (definition of dim is given as an inspirational example).
dim :: Matrix -> (Int,Int) --returns matrix dimension (number of rows and columns) dim m = if (not.isMatrix) m then error "Not a matrix" else (length m, length (head m))
isMatrix :: Matrix -> Bool --checks whether all rows have the same length isMatrix m = and [length (head m) == length a | a <- m]
I have done upto here and I am stuck on multSM.
multSM :: Double -> Matrix -> Matrix --multiplies a scalar and a matrix
when I do:
multSM d m = [[(b*a)| b<-[d], a<-(head m)]] or [map (*d) (head m)]
...I get (using Hugs):
Main> multSM 3 [[2,3,4],[1,3,4],[6,3,0]] [[6.0,9.0,12.0]]
So I solve 3 [2,3,4] but I do not know how to get the rest 3 [[1,3,4],[6,3,0].
Please help me on this problem.
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