[Haskell-cafe] Would you mind explain such a code ?

myFoldl :: (a -> b -> a) -> a -> [b] -> a myFoldl f z xs = foldr step id xs z where step x g a = g (f a x) I know myFoldl implements foldl using foldr. However i really donot know how it can do it ? Please shed a light one me, thanks! -- View this message in context: http://www.nabble.com/Would-you-mind-explain-such-a-code---tp25377949p253779... Sent from the Haskell - Haskell-Cafe mailing list archive at Nabble.com.