
24 Mar
2009
24 Mar
'09
11:36 a.m.
Martijn van Steenbergen
f x y = bam x y
This would introduce another matching of x on the outside of bam, and I don't know if this works without significantly messing with e.g. strictness. -- (c) this sig last receiving data processing entity. Inspect headers for copyright history. All rights reserved. Copying, hiring, renting, performance and/or quoting of this signature prohibited.