Re: [Haskell-cafe] Article review: Category Theory

18 Jan 2007


      Hi,

Am Donnerstag, den 18.01.2007, 16:45 +0000 schrieb David House:
...
On 18/01/07, Joachim Breitner  wrote:
...
(.) :: (b -> c) -> (a -> b) -> a -> c
id :: a -> a
therefore b = a
therefore _|_ :: a -> c
(This is mostly rough guesswork, I might be totally wrong)
That much is right, but remember that just because _|_ has type a -> c
doesn't mean it takes a parameter. Bottom can take any type, and I
don't think _|_ == \x -> _|_.
But if _|_ can take on any type, it can take on a -> b. And in what way
does it then differ from \x -> _|_?

Greetings,
Joachim

-- 
Joachim Breitner
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