In case you missed it the first time here is my query again: Hi I know we've already looked at the topic of function type calculation though last time I didn't have the chance to go through it thoroughly. So here it is again. Apologies for the repetition. I've had a try at calculating function types for two examples below. So to start with I'd be grateful for an assessment of my efforts. All comments are welcome. Thanks, Paul [1] funk f x = f (funk f) x f :: a x :: b funk f x :: c therefore funk :: a -> b -> c RHS f (funk f) x :: c f (funk f) :: d -> c x :: d f :: e -> d -> c funk :: h -> e f :: h unification f :: a = h = (e -> d -> c) x b = d therefore funk :: ((h -> e) -> b -> c) -> b -> c [2] w f = f f Assigning Types f :: a w f :: b therefore w :: a -> b RHS f f :: b f :: c -> b f :: c f :: a = b = c = (c -> b) therefore w :: (a -> a) -> a