But the qualifiers aren't arbitrary names, are they? On Apr 15, 2007, at 04:52 , Stefan O'Rear wrote:
I'm writing a code generator for C, and I'm trying to parse a C-like input language using LL(1) (parsec specifically). The syntax of declarators is giving me trouble: (simplified)
declaration = qualifiers >> (declarator `sepBy1` char ',') qualifiers = many1 name declarator = name
now if we have "<name> <name>", they are both parsed by the greedy many1 in qualifiers! I can make this work with some ugly rearranging:
declaration = fdeclarator >> many (char ',' >> declarator) fdeclarator = name >> many1 name declarator = name
is there a more elegant way?
Stefan _______________________________________________ Haskell-Cafe mailing list Haskell-Cafe@haskell.org http://www.haskell.org/mailman/listinfo/haskell-cafe