Re: [Haskell-cafe] what is f=f (not) doing ?

Neil Mitchell wrote:

I think your intuition is off. This isn't the problem of detecting Oh well, that happens when I try to help people when I don't really know what I'm talking about ;-)

I though it was impossible to detect a deadlock (and a blackhole is something like a deadlock no?) *before* it occured, but in this case, we're talking about detecting it *when* it occurs, no? And then raising an error instead of just blocking? Thanks, Peter