thanks! suppose we have
data Tree a = Leaf a | Branch (Tree a) (Tree a) deriving Show
and how I could define a function foo :: a -> Tree a that foo a = Leaf a where a is not a type of Tree foo b = b where b is one of the type of Tree (Leaf or Branch) ? The following code seems not working...... foo (Leaf a) = a foo a = Leaf a saying 'Couldn't match expected type `a' against inferred type `Btree a'' any idea? Thanks, Max From: Brandon S. Allbery KF8NH Sent: Thursday, January 01, 2009 7:35 AM To: Max.cs Cc: Brandon S. Allbery KF8NH ; beginners@haskell.org ; haskell-cafe@haskell.org Subject: Re: [Haskell-cafe] definition of data On 2009 Jan 1, at 2:32, Max.cs wrote: data Tree a = a | Branch (Tree a) (Tree a) deriving Show but it seems not accpetable in haskell ? You need a constructor in both legs of the type:
data Tree a = Leaf a | Branch (Tree a) (Tree a) deriving Show
-- brandon s. allbery [solaris,freebsd,perl,pugs,haskell] allbery@kf8nh.com system administrator [openafs,heimdal,too many hats] allbery@ece.cmu.edu electrical and computer engineering, carnegie mellon university KF8NH