Re: [Haskell-cafe] Endian conversion

7 Oct 2005


      On Friday 07 October 2005 14:50, Benjamin Franksen wrote:
...
First a version that should work (at least it compiles) for poke:
\begin{code}
instance (Storable a) => Storable (Endian a) where
    sizeOf (Endian a _) = sizeOf a
    alignment (Endian a _) = alignment a
    pokeByteOff p i (Endian a b) =
        if getHostByteOrder == b
            then pokeByteOff p i a
            else pokeByteOff p (sizeOf a - 1  - i) a
\end{code}
Note that even this breaks down for more complex types (i.e. records). 
For instance, with the obvious Storable instance of (Int16,Int16), the 
elements will get swapped, too. I can't see how to solve this in a 
generic way.

Ben