[Haskell-cafe] Re: what's the definition of "satisfy" and "<?>" ?

"z_axis@163.com" wrote:

I cannot understand the following code very well as i donot know the definition of "satisfy" and "".

Yes. Just look at the Parsec documentation, preferably Parsec 3, because Parsec versions prior to 3 were not well documented.

-- | Case-insensitive variant of Parsec's 'char' function. caseChar :: Char -> GenParser Char a Char caseChar c = satisfy (\x -> toUpper x == toUpper c)

-- | Case-insensitive variant of Parsec's 'string' function. caseString :: String -> GenParser Char a () caseString cs = mapM_ caseChar cs cs

This code looks incorrect to me. It should read: caseString :: String -> GenParser Char a () caseString cs = Parsec.try (mapM_ caseChar cs) cs Greets, Ertugrul. -- nightmare = unsafePerformIO (getWrongWife >>= sex) http://blog.ertes.de/