[Haskell-cafe] Re: How to decide if a number is an integer?

Hi, Here is an example: let l = fun num in if isIntegral l then l else 0 How to do the isIntegral thing? On Tue, Sep 29, 2009 at 1:58 PM, Magicloud Magiclouds wrote:

Hi,  In other weak-type language, `round i == i` would work. But in haskell, what should I do? Thanks. -- 竹密岂妨流水过 山高哪阻野云飞

-- 竹密岂妨流水过 山高哪阻野云飞