Re: [Haskell-cafe] for loops and 2d arrays in haskell

19 Jan 2007


      On 1/19/07, Sebastian Sylvan  wrote:
...
On 1/19/07, Sebastian Sylvan  wrote:
...
On 1/19/07, Fernan Bolando  wrote:
...
hi all
Since I am very new to haskell and still learning, I hope I will not
annoy poeple by asking the following question.
what is the simplest way to implement the following code in haskell?
it's just printing the
contents of 2D array.
for(i = 0; i < imax; i++){
        for(n = 0; n < nmax; n++){
                printf("%i:%i = %f\n", array[i][n]);
        }
}
Do you mean:
...
for(i = 0; i < imax; i++){
        for(n = 0; n < nmax; n++){
                printf("%i:%i = %f\n", i,n,array[i][n]);
        }
}
If so, how about:
sequence [ putStr (show i ++ ":" ++ show n ++ " = " show arr!(i,n) |
(i,n) <- indices arr ]
Sorry:
sequence [ putStrLn (show i ++ ":" ++ show n ++ " = " show arr!(i,n))
| (i,n) <- indices arr ]
Bah, it's way to early, forgot another parenthesis:
sequence [ putStrLn (show i ++ ":" ++ show n ++ " = " show (arr!(i,n)) )
                | (i,n) <- indices arr ]


-- 
Sebastian Sylvan
+46(0)736-818655
UIN: 44640862