[Haskell-cafe] Re: Can we come out of a monad?

"Edward Z. Yang" wrote:

Excerpts from Luke Palmer's message of Tue Aug 10 01:04:04 -0400 2010:

...

Except, of course, you want the signature

evalCont :: Cont r a -> a

Which is not possible. But I am not sure where all this discussion is coming from, Maybe and (r ->) cannot be broken out of. Isn't that example enough?

I'm confused... that's the type of evalCont, no?

There is no evalCont, there is runCont: runCont :: (a -> r) -> Cont r a -> r Note that Cont/ContT computations result in a value of type 'r': newtype Cont r a = Cont ((a -> r) -> r) Greets, Ertugrul -- nightmare = unsafePerformIO (getWrongWife >>= sex) http://ertes.de/