Re: [Haskell-cafe] take the keywords from a string

Hi, I tried to write function lexList by using an intermediate function lisOfString as below: module Lex where lexList :: String -> [String] lexList str = listOfString (lex str) lexList [] =[] listOfString :: [(String,String)] -> [String] listOfString [(s1,s2)] = s1: listOfString (lex s2) listOfString [("","")] = [] When I try function lisOfString as below, it runs forever (non-stop) although I have the stop criteria for it ?? Lex> lisOfString ["test1","test2(test3)"] Thanks in advance. S.

On 6/17/06, Neil Mitchell wrote:

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Hi

On 6/18/06, Sara Kenedy wrote:

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Sorry, I am not clear at some point in your answer:

1) The function lex :: String -> [(String,String)] and filter :: (a -> Bool) -> [a] -> [a] So, I did not see how filter can use the list of tuple string of lex.

You can write a function lexList, of type String -> [String], by repeatedly calling lex - its not too hard. Once you have this the filter will work.

Thanks

Neil