Re: [Haskell-cafe] cutting long strings into lines

On Sat, Sep 30, 2006 at 08:56:24PM +0400, Bulat Ziganshin wrote:

splitByLen len_f [] = [] splitByLen len_f xs = y : splitByLen len_f ys where (y,ys) = splitAt (len_f xs) xs ... so, "splitByLen len_f" should give you that you need, you need only to add checks for some additional conditions (first word in line is more than 80 bytes long, it is a last line) and removing of the extra space on each line

I came up with this solution that seem to be fine, to me. I does the checking of those additional conditions: findSplitP at = last . filter ( at then wrapLS at (tail remain) else tail remain then you can use lines/unlines to split it. Thanks for your help. Best regards, Andrea