Re: [Haskell-cafe] Generating random arguments for a function

* Stephen Tetley [2013-01-13 08:49:08+0000]

In general you can't do this whether you use pats of QuickCheck or not - `randomEvalute` would need to inspect the supplied function to see how many input parameters it has so it can list them, but there is no such introspection in Haskell.

This can be done with relatively simple type class hackery. In fact, QuickCheck already does that in order to generate arguments and print them in case of failure. Roman