I suppose it depends on your definition of straightforward but you can use the iterate function from Data.List to quickly define sequences like this. a = iterate (\x -> (1/5) * (x**2)) 10 On Mon, Mar 4, 2013 at 9:19 PM, Christopher Howard < christopher.howard@frigidcode.com> wrote:
Hi. My Haskell is (sadly) getting a bit rusty. I was wondering what would be the most straightforward and easily followed "procedure" for translating a recursively defined sequence into a Haskell function. For example, this one from a homework assignment.
quote: -------- a_1 = 10 a_(k+1) = (1/5) * (a_k)**2 --------
(The underscore is meant to represent subscripting what follows it.)
-- frigidcode.com
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