17 May
2006
17 May
'06
5:10 p.m.
big memory leak ... two parsers in sequence
A related question, are these two equivalents? foldl2 f g y z lst = (foldl f y lst, foldl g z lst) foldl2' f g y z lst = foldl (\(i, j) x -> (f i x, g j x)) (y, z) lst If no, is there some strictness that can be added to make them equivalent? And if so, could a compiler make this optimization as to avoid these sorts of space leaks? Thanks, Greg