Hi,
So far, I figured it out like this:
updateState ...
mbx <- (p3 >>= return . Just) <|> (return Nothing)
updateState ...
case mbx of
Just x -> return x
Nothing -> pzero
but this seems a bit clumsy - is there a more elegant solution?
---------- Forwarded message ----------
From: Dimitry Golubovsky
Date: Sat, May 31, 2008 at 10:12 AM
Subject: Parsec, updateState, and failure
To: haskell
Hi,
If a parser which updated user state fails, will such update be reverted?
Suppose we have two parsers combined with <|>
p = p1 <|> p2
p1 has the following:
p1 = try $ do
... -- getting something from the input stream
updateState (\st -> ...) -- updated state based on what gotten from the input
x <- p3 -- p3 should see updated state and return something
updateState (\st -> ...) -- updated state again (if p3 succeeded)
return x
If p3 fails, p1 fails too (second updateState will not be reached).
But what will p2 (tried next) see in the user state? Will it be state
after the first updateState, or will failure of p1 roll the update
back?
Is there any bracket- or try-catch-finally-like mechanism for Parsec?
Thanks.
--
Dimitry Golubovsky
Anywhere on the Web
--
Dimitry Golubovsky
Anywhere on the Web
