Re: [Haskell-cafe] Re: help with Haskell programming

Thanks a lot guys you were really helpful func f1 f2 x = (f1 x) || (f2 x) is working for me On Sun, Apr 18, 2010 at 6:27 PM, Thomas Davie wrote:

To do this, you need not just fmap (composition), but also ap, or the combined form, liftA2:

func = liftA2 (||)

Bob

On 18 Apr 2010, at 18:21, Keith Sheppard wrote:

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Using composition can be tricky with more than one arg. I just want to be sure you're not really looking for something like:

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func :: (a -> Bool) -> (b -> Bool) -> (a -> b -> Bool)

keeping with your given type I think you're looking for something like:

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func f1 f2 x = (f1 x) || (f2 x)

I'm sure there is a nice way to do this with function composition but I still find composition less intuitive than explicit args in cases like this.

On Sun, Apr 18, 2010 at 1:00 PM, Mujtaba Boori wrote:

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Thanks for helping me but I have another problem (sorry for asking) . I tried to figure it out . how about if I want to compare two kind with (&&) (||) for func :: (a -> Bool) -> (a -> Bool) -> (a -> Bool)

I tried some thing like func = ((||) .) This is the annoying part about Haskell . I can not understand composition .

On Sun, Apr 18, 2010 at 4:35 PM, Mujtaba Boori

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wrote:

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Hello I am kinda newbie in Haskell you can help help me with some programming I am trying to make function like for example func :: (a -> Bool) -> (a -> Bool) this function make calculation and return bool . I want to be able to make bool True when It is False and False when it is True while

returning

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the a. Thank you -- Mujtaba Ali Alboori

-- Mujtaba Ali Alboori

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-- Mujtaba Ali Alboori