
Jason Dusek wrote:
Stefan O'Rear
wrote: The only type that you are allowed to assume corresponds to a C int is CInt, in the Foreign.C.Types module. This probably isn't the problem, but it could make problems of its own on a 64-bit or otherwise weird system.
So say I turn everything back to pointers to CInt, what is the accepted way to convert from CInt to Int and CInt to Char?
Type class methods: -- for numbers like Int, CInt fromIntegral :: (Num b, Integral a) => a -> b -- for Char fromEnum :: (Enum a) => a -> Int toEnum :: (Enum a) => Int -> a
Is relying on the fact that CInt always wraps a Haskell integer an okay way to go?
I don't know what you mean by this.
I might was well learn these things now, before I get into bad habits.
Hope this helps, Claude -- http://claudiusmaximus.goto10.org