
On Mon, 28 Jul 2014 16:10:38 +0200, Daniil Frumin
Hi!
On Sun, Jul 27, 2014 at 12:55 AM, Henk-Jan van Tuyl
wrote: (\\) :: (Eq a) => [a] -> [a] -> [a] (\\) [] _ = [] (\\) _ [] = [] (\\) xs (y : ys) = delete y xs \\ ys
Is this actually correct? Shouldn't the second line be
(\\) x [] = x
?
You are right; as it was just to prove a point I didn't spend enough time reviewing/testing it. My life would have been much easier if I had chosen an area of expertise where showing my diploma was enough to prove that I am right. Regards, Henk-Jan van Tuyl -- Folding@home What if you could share your unused computer power to help find a cure? In just 5 minutes you can join the world's biggest networked computer and get us closer sooner. Watch the video. http://folding.stanford.edu/ http://Van.Tuyl.eu/ http://members.chello.nl/hjgtuyl/tourdemonad.html Haskell programming --