Re: [Haskell-cafe] How to get a file path to the program invoked?

Hi. On 5 December 2011 14:53, dokondr wrote:

Main System.Environment.Executable System.FilePath> "/abc" "/" "/"

Instead of getting "/abc/" I get "/". What am I doing wrong?

It thinks the second path is an absolute path. "Combine two paths, if the second path isAbsolute, then it returns the second." http://hackage.haskell.org/packages/archive/filepath/latest/doc/html/System-... HTH, Ozgur