This is a bit tricky. The type of 'f' is '[Int] -> IO [Int]', which means that the type of 'lst' is 'IO [Int]'. So fmap (+1) tries to add one to the [Int] underneath the 'IO' type constructor. You can either use two 'fmap's, the first to lift up to IO and the second to lift into the list, or you can use monad notation:
do lst <- f [1,2,3,4] return $ fmap (+1) lst
Does that make sense?
Take care,
Antoine
On Fri, Dec 17, 2010 at 11:04 AM, michael rice
I don't understand this error message. Haskell appears not to understand that 1 is a Num.
Prelude> :t 1 1 :: (Num t) => t Prelude> :t [1,2,3,4,5] [1,2,3,4,5] :: (Num t) => [t] Prelude>
Michael
===================
f :: [Int] -> IO [Int] f lst = do return lst
main = do let lst = f [1,2,3,4,5] fmap (+1) lst
===============================
Prelude> :l test [1 of 1] Compiling Main ( test.hs, interpreted )
test.hs:5:17: No instance for (Num [Int]) arising from the literal `1' at test.hs:5:17 Possible fix: add an instance declaration for (Num [Int]) In the second argument of `(+)', namely `1' In the first argument of `fmap', namely `(+ 1)' In the expression: fmap (+ 1) lst Failed, modules loaded: none. Prelude>
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