On 22 March 2010 13:49, adamtheturtle
Just tried the code shuffle :: Int -> [a] -> [a] shuffle i [] = [] shuffle i cards = [(cards!!i) : shuffle (fst pair) (delete (cards!!i) cards)] where pair = randomR (0, 51) (mkStdGen 42)
and I get:
Could not deduce (Eq a) from the context () arising from a use of `delete' at Cards.hs:(23,51)-(24,8) Possible fix: add (Eq a) to the context of the type signature for `shuffle' In the second argument of `shuffle', namely `(delete (cards !! i) cards)' In the second argument of `(:)', namely `shuffle (fst pair) (delete (cards !! i) cards)' In the expression: (cards !! i) : shuffle (fst pair) (delete (cards !! i) cards) Failed, modules loaded: none.
Any ideas?
Yes: do what it says! Hint: http://hackage.haskell.org/package/random-shuffle -- Ivan Lazar Miljenovic Ivan.Miljenovic@gmail.com IvanMiljenovic.wordpress.com