Re: [Haskell-cafe] Hi can u explain me how drop works in Haskell

ok maybe i should have read ahead. but still, i can see how to apply hunit, but not quickcheck. but quickcheck seems more powerful. On 2/26/07, Steve Downey wrote:

in addition, a good example of how to apply quickcheck would be really awesome. without using the standard drop <g>

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Here's my, probably very obvious, contribution.

What I'd like feedback on is

1) code seem ok? (hope so!) 2) What do you think of the tests I did to verify that this behaves the way I want? Is there a better / more idiomatic way to do this?

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thartman@linodewhyou:~/learning/haskell/lists$ cat drop.hs mydrop :: Int -> [Int] -> [Int] mydrop 0 xs = xs mydrop n xs = mydrop (n-1) (tail xs)

main = test test = do print test1 print test2 print test3

test1 = mydrop 3 [1,2,3] == [] test2 = mydrop 2 [1,2,3] == [3] test3 = mydrop 0 [1,2,3] == [1,2,3] thartman@linodewhyou:~/learning/haskell/lists$ runghc drop.hs True True True

2007/2/26, iliali16 :

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Hi I am trying to implement the function drop in haskell the thing is

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I

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I have been trying for some time and I came up with this code where I am trying to do recursion:

drop :: Integer -> [Integer] -> [Integer] drop 0 (x:xs) = (x:xs) drop n (x:xs) |n < lList (x:xs) = dropN (n-1) xs : |otherwise = []

So I want to understand how would this work and what exacttly should I

On 2/26/07, Thomas Hartman wrote: that put

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as an answer on line 4 couse that is where I am lost. I know I might got the base case wrong as well but I don't know what to think for it. I have done the lList as a function before writing this one. Thanks to those who can help me understand this. Thanks alot in advance! Have a nice day! -- View this message in context:

http://www.nabble.com/Hi-can-u-explain-me-how-drop-works-in-Haskell-tf329049...

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