j
k
j a
j l
On Donnerstag, 29. November 2012, 13:40:42, Johan Tibell wrote:
word2Double :: Word -> Double word2Double (W# w) = D# (int2Double# (word2Int# w)) On my (64-bit) machine the Haskell and C versions are on par.
word2Double :: Word -> Double word2Double (W# w) = D# (int2Double# (word2Int# w))
On my (64-bit) machine the Haskell and C versions are on par.
Yes, but the result is very different.
Back to the thread
Back to the list