Re: [Haskell-cafe] The range operator

At 12:28 07/04/2008, you wrote:

On Fri, Apr 4, 2008 at 10:49 PM, Andrew Coppin wrote:

...

More to the point, the range y..z goes in steps of y-z. ;-) [x,y..z] goes in steps of y-x ;-), [y..z] goes in steps of 1 (depending on the type).

Could you elaborate please?

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