Re: [Haskell-cafe] foldr (.) id

26 Oct 2012

      Can you please show some examples where it might be useful?
I miss the point.

Thanks,
Thiago.

2012/10/26 John Wiegley :
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Greg Fitzgerald  writes:
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I've recently found myself using the expression: "foldr (.) id" to compose a
list (or Foldable) of functions.
You want the Endo monoid:
ghci> appEndo (Endo (+ 10) <> Endo (+ 20)) $ 3
      33
John
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Re: [Haskell-cafe] foldr (.) id

Thiago Negri