Re: [Haskell-cafe] Hints for Euler Problem 11

But if the strings are all constant it's perfectly feasible to concatenate them at compile time. On 8/16/07, Kim-Ee Yeoh wrote:

Aaron Denney wrote:

...

On 2007-08-15, Pekka Karjalainen wrote:

...

A little style issue here on the side, if I may. You don't need to use (++) to join multiline string literals.

text = "If you want to have multiline string literals \ \in your source code, you can break them up with \ \backslashes. Any whitespace characters between \ \two backslashes will be ignored."

I find the first far more readable. The compiler should be able to assemble it all at compile time, right?

'Course not. The (++) function like all Haskell functions is only a /promise/ to do its job. What does "assembling at compile time" mean here:

s = "I will not write infinite loops " ++ s

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